链接：

题意：已知 n，a，求 b，c 使 a^n + b^n = c^n 成立。

题解：费马大定理

1.a^n + b^n = c^n，当 n > 2 时无解；

2.

当 a 为奇数

a = 2 * k + 1;

c = k ^ 2 + (k + 1) ^ 2;

b = c - 1;

当 a 为偶数

a = 2 * k + 2;

c = 1 + (k + 1) ^ 2;

b = c - 2;

#include 
     
      using namespace std;const double EPS = 1e-6;const int INF = 0x3f3f3f3f;const int mod = 1e9 + 7;const int maxn = 1e5 + 10;long long n, a, b, c;int main(){    int T;    scanf("%d", &T);    while(T--){        scanf("%lld%lld", &n, &a);        if(n == 0 || n > 2){            puts("-1 -1");            continue;        }        if(n == 1){            printf("%lld %lld\n", a, a<<1);            continue;        }        if(a & 1LL){            long long k = a / 2;            c = k * k + (k + 1) * (k + 1);            b = c - 1;        }        else{            long long k = a / 2 - 1;            c = 1 + (k + 1) * (k + 1);            b = c - 2;        }        printf("%lld %lld\n", b, c);    }    return 0;}